The answer will depend on whether the interval in one or two sided. One-sided: Z < 1.28 or Z > -1.28 Two-sided: -1.64 < Z < 1.64
You don't. There are times when you use 99% or 99.5%, and others where you will settle for 90%. The percentage chosen will depend on the implications of making the wrong decision.
90 is 100 percent. 90/100 = 0.9 is 1 percent. This value times 25 gives you 25 percent. Solution: 22.5
It may stand for the number 150 (Roman numbers). In statistics, CL usually refers to "Confidence Level," which establishes a likelihood (typically 90 or 95%) an estimated value will fall within a given Confidence Interval (a range of estimated values). For example... [I'll get more done on this later]
With silver over $30.00 per ounce the intrinsic value is about $11.00.
decrease
The answer will depend on whether the interval in one or two sided. One-sided: Z < 1.28 or Z > -1.28 Two-sided: -1.64 < Z < 1.64
The answer depends on whether the test is one-tailed or two-tailed.One-tailed: z = 1.28 Two-tailed: z = 1.64
1.0966
The user selects the confidence level. It could also be 90 or 99 or 99.9 or another value.
You don't. There are times when you use 99% or 99.5%, and others where you will settle for 90%. The percentage chosen will depend on the implications of making the wrong decision.
The confidence interval will be Pi+-z*spz5%= 1.6449Pi = x/nSp = Sqrt(Pi(1-Pi)/n)Pi ~= 0.5694Sp = Sqrt(.5694*0.4306/144) ~= 0.0413Pi - 0.0679 < p < Pi + 0.06790.5016 < p < 0.6373You can do this on your TI-83/84 with 1-PropZInt (Stat->Tests->A)
To find 90 percent of a value, multiply the value by 0.9. In this instance, 0.9 x 2 = 1.8 kilometres.
10% of 90 = 990% 0f 10 = 9(10% of 90) + (90% of 10) = 18
90 is 100 percent. 90/100 = 0.9 is 1 percent. This value times 25 gives you 25 percent. Solution: 22.5
If there are any grounds for assuming that the prices are Normally distributed (in fact, there are none), then a 90% confidence interval is (3.72, 10.04).
It may stand for the number 150 (Roman numbers). In statistics, CL usually refers to "Confidence Level," which establishes a likelihood (typically 90 or 95%) an estimated value will fall within a given Confidence Interval (a range of estimated values). For example... [I'll get more done on this later]