2541
847 x 7 = 7929
1 x 847, 7 x 121, 11 x 77
Use a calculator, and divide 574 / 7.
With no remainder, 7 goes into 6,000, 857 times. 6000 / 7 = 857.143
121
Divide the diameter by 2.
7 times 121 = 847
The positive integer factors of 847 are: 1, 7, 11, 77, 121, 847
It is: 7*11*11 = 847
sqrt(847) = 11*sqrt(7).
847 = 7 x 11 x 11
Factors of 385: 1, 5, 7, 11, 35, 55, 77, 385.Factors of 847: 1, 7, 11, 77, 121, 847.GCF (385, 847) = 77
2541
Well you should probably make a tree. So first you have to find out at least the smallest number that goes into 847. 847 goes into 7, which is the smallest, yes. 847 divided by 7 equals 121. 121 goes into nothing only 1. So I think that the prime factor would be 847 and I don't know about the other prime factors. Let me check hold on. Yep that is it. Only 121. Just try to make a tree they help out the best, I think anyway. =)
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1, 7, 11, 77, 121, 847 are the factors of 847.. or 847 = 11*77 ..inorder to make it a perfect square ..u need to multiply 7,11 to the existing number as 11 ,7 are prime numbers. so the least number will be 11*77*11*7