Q: What multiples of 7 in part are exactly divisible by 3?

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1. Sum of digits (12) is divisible by 3, so number is divisible by 3 2. It's an even number so it's divisible by 2 3. If it's divisible by both 3 and 2 then it's divisible by 3 x 2, ie 6.

If a number is divisible by 2 (an even number) and 3 (the sum of the digits is divisible by 3) then the number is divisible by 6.

33 multiples of 3 10 multiples of 10 -3 multiples of both 40 total

12 and all multiples of 12.

Every one of the infinite number of multiples of 9 is, as well as roughly 1/3 of the multiples of 3. There sure are a huge number of them.

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They are multiples of 3

yes since 9 is divisible by 3 all its multiples are as well

6 and its multiples are divisible by 2 and 3.

Multiples of 12.

1. Sum of digits (12) is divisible by 3, so number is divisible by 3 2. It's an even number so it's divisible by 2 3. If it's divisible by both 3 and 2 then it's divisible by 3 x 2, ie 6.

12 and its multiples

Any of its multiples

Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5

The common multiples of 3 and 9 are 9, 18, 27 and so on.Any number that is divisible by 9 is also divisible by 3. This is because 9 is divisible by 3, so any multiples of 9 must also be divisible by three.78 117 156 195 234 273 312 351 390and so on ...

If a number is divisible by 2 (an even number) and 3 (the sum of the digits is divisible by 3) then the number is divisible by 6.

A multiple of 3 is a number evenly divisible by 3.

the # needs to be divisible by 2 and 3.