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To find multiples of 7 that are exactly divisible by 3, we need to find numbers that are common multiples of both 7 and 3. The least common multiple of 7 and 3 is 21. Therefore, every multiple of 21 will be exactly divisible by both 7 and 3. Some examples of such numbers include 21, 42, 63, 84, and so on.
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How can you tell without dividing by 6 that 138 is exactly divisible by 6?
1. Sum of digits (12) is divisible by 3, so number is divisible by 3 2. It's an even number so it's divisible by 2 3. If it's divisible by both 3 and 2 then it's divisible by 3 x 2, ie 6.
What is the rule for multiples of 6?
If a number is divisible by 2 (an even number) and 3 (the sum of the digits is divisible by 3) then the number is divisible by 6.
How many numbers between 1 and 100 (inclusive) are divisible by 3 or 10?
33 multiples of 3 10 multiples of 10 -3 multiples of both 40 total
What numbers are divisible by 3 and 4?
12 and all multiples of 12.
What is divisible by9?
Every one of the infinite number of multiples of 9 is, as well as roughly 1/3 of the multiples of 3. There sure are a huge number of them.
