Let the number be 'm' & 'n'
Hence
mn = 20
m + n = -5
m = -5 -n
Substitute
n(-5-n) = 20
-5n - n^2 = 20
n^2 + 5n + 20 = 0
It is now in quadratic form , so use quadratic eq'n
n = { - 5 +/- sqrt[(5_^2 - 4(1)(20)]} / 2(1)
n = { - 5 +/- sqrt[25 - 80]}/ 2
n = { - 5 +/'- sqrt[-80]} / 2
This is unreseolved because you cannot take the square root of a negative number.
5
9 and 11.
4 and 5
-27
29
To find two numbers that add to 20 and multiply to 29, we can set up a system of equations. Let's call the two numbers x and y. We have the following equations: x + y = 20 and x * y = 29. By solving these equations simultaneously, we find that the two numbers are 5 and 15.
26
20
-70
2 x 10 = 20 2 + 10 = 12
-12.385165 and -1.614835
-3 and -3.
-10 and 1