Subtract 108.
That completely depends on the value of 'x'. Whatever 'x' happens to be at the moment, you must add to this expression an amount equal to triple-x less than 7. In other words, the expression [ 7 - 3x ] must be added.
to find the domain first check all the possibilities of the denominator attaining a value of zero then if the function has any thing inside a square root, the expression inside the root must be always greater than or equal to zero.If the square root is in the denominator then the expression inside must be just greater than zero but not equal to zero.
That is not an equation because there is no equal sign. In order for y to be a function of x, y must equal the rest of the values. So assuming that your expression was equal to 0. To make y a function of x, add 3y to both sides and then divide the equation by 3. y=5/3x-50
To calculate the perimeter, by definition, you must add up all the sides. The details, of course, vary from case to case. For example, if you have an arbitrary triangle, the expression would be something like side1 + side2 + side3 (or whatever the sides are called). In some cases you can simplify the resulting expression; in an isosceles triangle, you have two equal sides, so you get an expression similar to a + a + b = 2a + b. In a rectangle, opposite sides are equal, so you get perimeter = a + b + a + b = 2a + 2b or 2 (a + b).
stooped
It is: x/8.4 times 8.4 = x
Not possible.
That completely depends on the value of 'x'. Whatever 'x' happens to be at the moment, you must add to this expression an amount equal to triple-x less than 7. In other words, the expression [ 7 - 3x ] must be added.
you have to undo what ever's being done to the variable :p
in order to make two opposing sides happy with the decision. the justice must be done that is fair and equal to both sides.
You must look at the condition when the expression is greater or equal to zero and the case (condition) when it is less that zero.
Evaluate the criteria before executing the conditional expression. In pseudocode:result1 = evaluate( criteria1 );result2 = evaluate( criteria2 );if( result1 && result2 ) initiate_event;Note that this is not the same as the following:if( evaluate( criteria1 ) && evaluate( criteria2 )) initiate_event;If the evaluation of criteria1 fails for any reason, then the whole expression fails and criteria2 is never evaluated. so if the evaluations must be done independently of each other, then they must be done prior to the conditional expression, storing the results for use in the conditional expression.
In an ideal scenario, the work done with a machine is the same as work done without a machine because the total work output must be equal to the total work input. While machines can make work easier by multiplying force or changing the direction of force, they cannot create energy. Therefore, the work done by the machine should ideally be equal to the work done without a machine.
It must be done with a computer program.
All sides must be equal in length and each interior angle must be equal in degrees
to find the domain first check all the possibilities of the denominator attaining a value of zero then if the function has any thing inside a square root, the expression inside the root must be always greater than or equal to zero.If the square root is in the denominator then the expression inside must be just greater than zero but not equal to zero.
Gordon Hewart, in Rex v. Sussex Justices ex parte McCarthy (1924), who literally said "Not only must Justice be done; it must also be seen to be done."(The sentiment is obviously in the English tradition, so that the only possibility other than a British jurist would have been an American jurist.)