(x)=(1- cosh (ix))/2
how do you take one away from nine and leave ten
If x is the natural number, 1/x is the reciprocal.
I say 21. I think C stands for 100. L is for 50. X is 10. And IX equals nine.
The next number in the pattern is 125.This pattern is determined by cubing the numbers.First number = 1 x 1 x 1 = 1Second number = 2 x 2 x 2 = 8Third number = 3 x 3 x 3 = 27Fourth number = 4 x 4 x 4 = 64Fifth number = 5 x 5 x 5 = 125etc.
XVII times XVI = X(XVII)+V(XVII)+I(XVII) Multiplying out the brackets = CLXX+LXXXV+XVII Collecting numerals and simplifying = CCLXXII Therefore XVII (17) times XVI (16) equals CCLXXII (272) Numerical values: C=100, L=50, X=10, V=5 and I=1. David Gambell, Merseyside, England.
I, II, III, IV, V, VI, VII, VIII, IX, X, XI, XII, XIII, VX, XV, XVI, XVII, XVIII, XIX
I, II, III, IV, V, VI,VII,VIII, IX, X, XI, XII, XIII, XIV, XV, XVI,XVII,XVIII, XIX, XX.
You write them: I, II, III, IV, V, VI, VII, VIII, IX, X, XI, XII, XIII, XIV, XV, XVI, XVII, XVIII, XIX, XX.
In addition notation: I, II ,III, IIII, V, VI, VII, VIII, VIIII, X, XI, XII, XIII, XIIII, XV, XVI, XVII, XVIII, XVIIII, XX and XXI. In subtractive notation: I, II, III, IV, V, VI, VII, IIX, IX, X, XI, XII, XIII, IXV, XV, XVI, XVII, IIXX, IXX, XX and XXI.
Either I-XX or I, II, III, IV, V, VI, VII, VIII, IX, X, XI, XII, XIII, XIV, XV, XVI, XVII, XVIII, XIX, XX.
9 is IX. Roman numerals for 1 - 27: I, II, III, IV, V, VI, VII, VIII, IX, X, XI, XII, XIII, XIV, XV, XVI, XVII, XVIII, XIX, XX, XXI, XXII, XXIII, XXIV, XXV, XXVI, XXVII
I ii iii iv v vi vii viii ix x xi xii xiii xiv xv xvi xvii xviii xix xx xxi xxii xxiii xxiv
I,ii,iii,iv,v,vi,vii,viii,ix,x,xi,xii,xiii,xiv,xv,xvi,xvii,xviii,xix,xx,xxi,xxii,xxiii,xxiv,xxv,xxvi,xxvii,xviii,xxix,xxx
They are: I II III IV V VI VII VIII IX X XI XII XIII XIV XV XVI XVII XVIII XIX XX XXI XXII XXIII XXIV XXV
I ii iii iv v vi vii viii ix x xi xii xiii xiv xv xvi xvii xviii xix xx xxi xxii xxiii xxiv xxv xxvi xxvii
The Roman number XVII is 17 (seventeen).Note, X = 10, V = 5, II = 2