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The sequence appears to be alternating between cubes of integers and their negative counterparts. The first number is -4 cubed, the second is 5 cubed, the third is -6 cubed, the fourth is 7 cubed, and the fifth is -8 cubed. Therefore, the next number in the sequence would be 8 cubed, which is 512.
64 125 216 343 512 729Bold numbers are the missing in the sequence
128. 1+1=2 2+2=4 4+4= 16 16+16= 32 32+32= 64 64+64 = 128 128+128 = 256 256+256 =512 512+512= 1024 Each time take the answer from the previous problem and double it to find the next number in the sequence.
Yes, 512 is divisible by 4. A number is divisible by 4 if the last two digits of the number form a number that is divisible by 4. In this case, the last two digits of 512 are 12, which is divisible by 4. Therefore, 512 is divisible by 4.
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