Q: What number begins this sequence 10 11 21 31 41 1401 16 512?

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The sequence appears to be alternating between cubes of integers and their negative counterparts. The first number is -4 cubed, the second is 5 cubed, the third is -6 cubed, the fourth is 7 cubed, and the fifth is -8 cubed. Therefore, the next number in the sequence would be 8 cubed, which is 512.

64 125 216 343 512 729Bold numbers are the missing in the sequence

128. 1+1=2 2+2=4 4+4= 16 16+16= 32 32+32= 64 64+64 = 128 128+128 = 256 256+256 =512 512+512= 1024 Each time take the answer from the previous problem and double it to find the next number in the sequence.

It is: 888 = 512

500

Related questions

The sequence appears to be alternating between cubes of integers and their negative counterparts. The first number is -4 cubed, the second is 5 cubed, the third is -6 cubed, the fourth is 7 cubed, and the fifth is -8 cubed. Therefore, the next number in the sequence would be 8 cubed, which is 512.

64 125 216 343 512 729Bold numbers are the missing in the sequence

It is: 64

180 / 512 = 0.3515625 0.3515625 x 512 = 180

512

83 = 512

How about: 2 to the power of 9 = 512

128. 1+1=2 2+2=4 4+4= 16 16+16= 32 32+32= 64 64+64 = 128 128+128 = 256 256+256 =512 512+512= 1024 Each time take the answer from the previous problem and double it to find the next number in the sequence.

No.

It is: 1/512 times 512 = 1 or 512 to the power of 0 = 1

It is: 888 = 512

It is 8 cubed equals 512