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What number can be divided by 2 3 4 5 6 7 8 9 and always give you a remainder of 1?
Wiki User
∙ 6y ago
If you multiply all those numbers together you will get a number of which they are all a factor.
Each of them will divide evenly into it with no remainder. That number is 362,880
So, if we add 1 to that, we will always get a remainder of 1 when we divide by those numbers.
- 362,881 / 2 = 181,440 +1
- 362,881 / 3 = 120,960 +1
- 362,881 / 4 = 90,720 +1
- 362,881 / 5 = 72,576 +1
- 362,881 / 6 = 60,480 +1
- 362,881 / 7 = 51,840 +1
- 362,881 / 8 = 45,360 +1
- 362,881 / 9 = 40,320 +1
- 362,881 / 10 = 36,288 +1
The same result can be found by adding 1 to their LCM. The smallest such number is 2521.
Wiki User
∙ 6y ago
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