OK, SO THE answer is 318 and 477. I got this by multiplying 3 and 53 and then multiplying it by 2 to get 318 and adding 159 to 318 (or multiplying 159 by 3) to get 477. Both of these work.
500 + (300/23) = 513.0434782608695652173913 recurring (that is, 513.04347826086956521739130434782608695652173913...)
1.6667
300 Find the difference (500-100=400) then halve the sum(200). Add the halved sum to the lowest number in the equaion(100) or subtract the halved sum(200)from the largest number in the equation(500) one:500-100=400 two:400/2=200 Three: 200+100=300 or 500-200=300
0.2
The number halfway between 25300 and 26500 is (25300 + 26500) ÷ 2 = 25900.
Any number between 300 and 500. Working with integers it would be 301-499.
500 + (300/23) = 513.0434782608695652173913 recurring (that is, 513.04347826086956521739130434782608695652173913...)
1.6667
400
300 Find the difference (500-100=400) then halve the sum(200). Add the halved sum to the lowest number in the equaion(100) or subtract the halved sum(200)from the largest number in the equation(500) one:500-100=400 two:400/2=200 Three: 200+100=300 or 500-200=300
A number between 1 and 500 is composite if it can be divided, without remainder, by a number other than 1 and itself.
470, for one.
0.2
The number halfway between 25300 and 26500 is (25300 + 26500) ÷ 2 = 25900.
99
450 is half way between 300 and 600.
Can you simplify 300/500