Seven goes into both 63 and 77
To find the highest common factor (HCF) of 77, 132, and 143, we first need to break down each number into its prime factors. 77 = 7 x 11 132 = 2^2 x 3 x 11 143 = 11 x 13 Next, we identify the common prime factors among the numbers, which are 11. Therefore, the HCF of 77, 132, and 143 is 11.
Do your math.132/5=26.4.
77 over 10 = 77/10
7 could go into 77 by.7 and 11
1 and 11.
132/77 = 12/7
gcf of 33 77 and 132
The GCF of 33, 77, and 132 is 11.
The GCF is 11.
Since 37 is a prime number, the GCF is 1
The GCF of 55, 77, and 132 is 11.It is 11
Oh, dude, the greatest common factor of 77, 132, and 143 is 11. It's like the cool kid that all these numbers have in common. So, if you're throwing a math party with these numbers, 11 is the VIP guest that gets in everywhere.
This can be solved using the cosine rule to find the length of side EF, and the sine rule to find angle E The cosine rule is: a² = b² + c² - 2bc cos A we have: A = G = 132° a = EF b = EG = 77 inches c = FG = 89 inches (the assignment of b and c doesn't matter as they are the two sides of the angle A and are interchangeable for the cosine rule), giving: EF² = 77² + 89² - 2×77×89×cos 132° → EF = √(77² + 89² - 2×77×89×cos 132°) The sine rule is: (sin A)/a = (sin B)/b = (sin C)/C we have: A = G = 132° a = EF = √(77² + 89² - 2×77×89×cos 132°) inches (found above) C = E c = FG = 89 inches → (sin 132°)/√(77² + 89² - 2×77×89×cos 132°) in = (sin E)/89 in → sin E = (89 sin 132°)/√(77² + 89² - 2×77×89×cos 132°) → E = arc sin((89 sin 132°)/√(77² + 89² - 2×77×89×cos 132°)) → E ≈ 25.8° → E ≈ 26° to the nearest degree
11
11
It is: 11