It is '3' to the power(exponent) of 'n-1'.
#1 ; 3^(1-1) = 3^(0) = 1
#2 ; 3^(2 -1) = 3^(1) = 3
#3 ; 3^(3-1) = 3^(2) = 9
#4 ; 3^(4-1) = 3^(3) = 27
#5 ; 3^(5-1) = 3^(4) = 81
#6 ; 3^(6-1) = 3^(5) = 243
#n th term ; 3^(n - 1)
et seq.,
The next number is 49+8 = 57
27
27
45 54
25
The next number is 49+8 = 57
27
27
45 54
27
The series consists of the cubes of consecutive integers: (1^3), (2^3), (3^3), and (4^3). The next number in the series would be (5^3), which is (125). Therefore, the next number is 125.
Next number= 27 X 3 = 81.
105 1st number is 13 = 1 2nd number is 23 = 8 3rd number is 33 = 27 So, 4th number is 43 = 256
The series alternates between two patterns: one where numbers are multiplied by 3 and then reduced (18 to 27 to 36) and another where numbers are multiplied by 4 and then reduced (81 to 72 to 63). Following this pattern, the next number after 36 (from the first sequence) would be 45 (36 multiplied by 1.25), and after 63 (from the second sequence), the next number would be 54 (63 reduced by 9). Thus, the next number in the series is 45.
the numbers next in series are 35,43,51,... any two consecutive terms has a difference of 8
25
243