both these number go into the number 112
The number = 9Working:n - 5 = 13 - n(+ 5 on both sides)n = 18 - n(+ n on both sides)n + n = 18= 2n = 18(divide both sides by 2)n = 9So...9 - 5 = 13 - 9(9 - 5 = 4)(13 - 9 = 4)
32. 4x8= 32. They can both go into 32
13 less than 4 times a number 13 less than is "-13" 4 times a number is "4x" 4x-13■
20 and any multiples of twenty
Since 2 and 4 go into 8, the only numbers you have to deal with are 8 and 13. Since 13 is prime, the smallest number they will both go into is 8*13 = 104 ■
If you know that 13 is prime, then you know that the number 1 can go into it. Factors : 1 ( Of Course ) , & 13. Is Its Factors. If The Number 13 Has An Even Number Then You Know That 2 Should Go Into 13. (2,4,6,8, and 0) If The Number 13 Has Two Zeros ( 00 )s At The End Then 4 Can Go Into It. (00) or (4) If The Number 13 Has A Zero(0) Or (5) At The End Then 5 Can Go Into It. If The Numbers 2 & 3 (BOTH) Go Into 13 Then 6 Can Automatically Go Into 13. If It Ends With A ( 0 ) Then 10 Can Go Into It.
13 is a prime number so only 13 and one can go into it
Well, no number can go into both 4 and 11, but the factors of 4 are 1, 2 and 4. The factors for 11 are 1 and 11.Hope I helped! :)* * * * *Mainly correct but wrong to say that "no number can go into both 4 and 11" and then contradict that statement by stating that 1 is a factor of both!
both these number go into the number 112
140
16
The number = 9Working:n - 5 = 13 - n(+ 5 on both sides)n = 18 - n(+ n on both sides)n + n = 18= 2n = 18(divide both sides by 2)n = 9So...9 - 5 = 13 - 9(9 - 5 = 4)(13 - 9 = 4)
Suppose it is n Then n/11 = 13 + r4 = 13 + 4/11 Multiply both sides by 11: n = 11*13 + 4 = 143 + 4 = 147
4m-17m+4 = 0 -13m = -4 Divide both sides by -13 remembering that a negative number divided into a negative number is equal to a positive number: m = 4/13
9991
It is 4/13.