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Twice the quotient of a number m and 35 can be expressed as 2 * (m / 35). This simplifies to 2m / 35, which is the same as m / 17.5. Therefore, twice the quotient of a number m and 35 is equivalent to half of the number m divided by 17.5.
m/2
In the metric system "m" is the abbreviation for metresmaking the number a measure of distance.
either m/10 or 10/m (/=divide)
m + 4
Momentum = (mass x velocity) = M V If velocity is doubled, then new momentum = (M x 2V) = 2 x (M V) = double the original momentum. ========================= Kinetic energy = 1/2 M V2 If 'V' is doubled, then new KE = (1/2 M) (2V)2 = (1/2 M) (4V2) = 4 (1/2 M V2) = 4 times original KE.
You solve the equation for kinetic energy for mass. KE = (1/2) m v2 (1/2) m v2 = KE m = 2 KE / v2
Ek = 1/2 * m * v^2 Ek = 1/2 * 161 g * (39 m/s)^2 Ek = 1/2 * 161g * (1kg / 1000g) * (39 m/s)^2 Ek = 254 kgm^2/s^2 Ek = 254 J
Although the units of the kinetic energy aren't given, we have to assume that the "3,000"are joules ... the SI unit of energy; otherwise we can't go anywhere at all with this question.K.E. = 1/2 m V2 = 3,000 joulesm V2 = 6,00080 V2 = 6,000V2 = 6,000/80 = 75V = sqrt(75) = 8.66 meters per second (rounded)
The ball at a height has a certain potential energy and the potential energy in relation to plate at the highest point after rebound will be equal to ball's total kinetic energy an instant after rebound. The first figure of 1.80 m isn't necessary to perform calculations.Ep = m * g * hEk = m * v2 / 2Ek = Ep = 0.1 * 9.81 * 1.25 = 1.22625 Jv = sqrt(2 * Ek / m) = 4.9523 m/s
Frantis ek Koranda has written: 'KSC a politicky syste m C SSK'
Yeah
To find the volume of 0.075 M NaCl solution that can be made, you can use the formula C1V1 = C2V2. Plugging in the values, we get (9.0 M)(450 mL) = (0.075 M)(V2). Solving for V2 gives V2 = 1.1 L. Therefore, 1.1 L of 0.075 M NaCl solution can be made by diluting 450 mL of 9.0 M NaCl.
The derivative of kinetic energy with respect to time is equal to the power (rate of change of energy) of the system. This can be found using the equation ( P = \frac{dE_{\text{kin}}}{dt} = F \cdot v ), where ( F ) is the force applied and ( v ) is the velocity of the object.
For all dilution/ concentration problems you use the simple equation: M1V1 = M2V2 2.40*V2 = 8.25*25 V2 = (8.25*25)/2.40 V2 = 85.9mL Final volume will be 86mL.
mT = 5000 kg v1 = 22 m/s v2 = 20 m/s Conservation of momentum: Pi - Pf = 0 mT*v1 = (mT+mw)*v2 mw = (mT * v1 / v2) - mT Mass of rain: mw = 500 kg
The kinetic energy (Ek) of the soccer ball can be calculated using the formula: Ek = 0.5 * mass * velocity^2. Plugging in the values, Ek = 0.5 * 1 kg * (10 m/s)^2 = 50 J. The kinetic energy of the soccer ball is 50 Joules.