There are infinitely many numbers between any two different numbers. To get the number that is exactly in the middle, add the two numbers, then divide the result by 2.
The number exactly between 0 and 3 is 1.5. This is determined by finding the average of the two numbers, which is calculated by adding them together and dividing by 2. In this case, (0 + 3) / 2 = 1.5.
20
4
In equation form, when the number is x: x2 + 3 = 4x x2 - 4x + 3 = 0 (x - 1)(x - 3) = 0 x - 1 = 0 or x - 3 = 0 x = 1 or x = 3
Both 30 and 20 are equal to 1. Any real number raised to the zero power is 1.
The number exactly between 0 and 3 is 1.5. This is determined by finding the average of the two numbers, which is calculated by adding them together and dividing by 2. In this case, (0 + 3) / 2 = 1.5.
No. The sum of a negative number and a positive number has the absolute value of their difference and the sign of whichever of them was bigger - in absolute terms. So -3 + 4 = +1 (diff between 3 and 4 is 1, and the bigger number, 4, is positive) -3 + 3 = 0 (diff between 3 and 3 is 0, the sign for zero does not matter) -3 + 2 = -1 (diff between 3 and 2 is 1, and the bigger number, 3, is negative)
As an integer is a whole number (0, 1, 2, 3,and so on), I would say "No."
Some numbers between 0 and 1 are .1; .2; .3 These numbers are one-tenth, two-tenths, and three tenths. All fractions whose top number is one or higher and whose top number is less than its bottom number are all numbers between 0 and 1. For example, 1/2; 4/5; 7/8; 35/40 are all numbers between 0 and 1.
between 0 and 1
3/4= .75 which is between 0 and 1.
When you add all the digits of a number and it is a factor of 3, that means the larger number is a factor of 3. For example: 101 is not because 1+0+1=2, However, 102 is because 1+0+2=3 and 3*1-3.
I would say it was 0:-5 -4 -3 -2 -1 0 1 2 3 4 5
Not possible ! The digits add as follows... 1+0+1 = 2 1+0+2 = 3 1+0+3 = 4 1+0+4 = 5 1+0+5 = 6 1+0+6 = 7 1+0+7 = 8
20
4
In equation form, when the number is x: x2 + 3 = 4x x2 - 4x + 3 = 0 (x - 1)(x - 3) = 0 x - 1 = 0 or x - 3 = 0 x = 1 or x = 3