If its divisible by 5 AND 2 it must be divisible by 10
So you just have to pick the only number between 21 and 39 that's divisible by 10
To determine if 21789 is divisible by a certain number, we need to check if 21789 divided by that number results in a whole number without a remainder. 21789 is divisible by 1, 3, 7, 13, 21, 39, 49, 91, 147, 273, 637, and 1911. This can be determined by performing the division operation and checking for a remainder of 0.
All real numbers are divisible by four. However, no numbers with decimal extensions are evenly divisible by four. The only numbers evenly divisible by four between 30 and 39 are 32 and 36. Otherwise, including decimals, there would be an infinite number of rational numbers between those limits divisible by four, and infinitely more than that if the real numbers are included (numbers that cannot be represented by terminating or repeating continued decimal expansions).
There are 39 natural numbers between 1,000 and 1,500, inclusive, that are divisible by 13.
21
39 and 40
There are eight numbers between 0 and 50 that are divisible by three but not by two: 3, 9, 15, 21, 27, 33, 39, 45.
3,9,15,21,27,33, 39 and 45
40 is nearest to 39 and is exactly by divisible 4
All multiples of 39, which is an infinite number.
Because it is divisible by numbers other than 1 and itself. 39 is divisible by 1, 3, 13, 39.
3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, 48.
The number 9 is the smallest, but there are an infinite number of answers to the question. 15, 21, 27, 33, 39, and 45 are some more.
9, 21, and 39 are divisible by three, so they are composite. 3, 17, and 41 have only two factors, 1 and itself, so they are prime.
yes it is divisible by 1,2,10,5 and 39
composite 3 goes into 3 or 30 3 goes into 9 so 3 goes into 39 13 + 13 + 13 = 39 = 3 x 13 ------------------------------------- Applying a divisibility test: To be divisible by 3, sum the digits of the number and if this sum is divisible by 3, then the original number is divisible by 3. As the test can be repeated on the sum, repeat the summing until a single digit remains; only if this number is one of {3, 6, 9} is the original number divisible by 3. For 39 this gives: 39 → 3 + 9 = 12 12 → 1 + 2 = 3 3 is one of {3, 6,9} so 39 is divisible by 3. As 39 is divisible by 3 (that is 3 is a factor of 39 that is less than 39) and 3 is greater than 1 then 39 is a composite number.
The number halfway between 18 and 21 can be found by taking the average of the two numbers. To do this, add 18 and 21 together to get 39, then divide by 2 to get 19.5. Therefore, the number halfway between 18 and 21 is 19.5.
12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45, and 48. As you may have noticed, all you have to do is count every third number.