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Split the number into its alternate digits.Sum the digits in each setIf the difference between their sums is zero (0) or divisible by 11 then the original number is divisible by 11.ExamplesIs 1289324 divisible by 11?Split into alternate digits: 1_8_3_4 and _2_9_2 Sum each set of digits:1_8_3_4 -> 1+8+3+4 = 16_2_9_2 -> 2+9+2 = 13Difference between the sums: 16 - 13 = 3, not divisible by 11; so original number 1289324 is not divisible by 11.Is 19407278 divisible by 11?Split into alternate digits: 1_4_7_7 and _9_8_2_6 Sum each set of digits:1_4_7_7 -> 1+4+7+7 = 19_9_0_2_8 -> 9+0+2+8 = 19Difference between the sums: 19 - 19 = 0; so original number 19407278 is divisible by 11.
It is divisible by 2 [2*19 = 38] and a number that is divisible by two is an even number.
Well, darling, 19 is only divisible by 1 and 19 itself. It's a prime number, which means it's too fabulous to be divided by any other number and still give a whole number result. So, if you're looking to break up 19 into equal parts, tough luck, honey.
There are an infinite number. Let's start with 1, which is only divisible by 1. Then any prime number greater than 5: 7, 11, 13, 17, 19, 23, 29, 31, ... {there are an infinite number of these} Then multiply any of those two (or more) prime numbers together, such as 49 [7 x 7], 77 [7 x 11], 121 [11 x 11], 1729 [7 x 13 x 19], etc.
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