It is: (3.9+6.2)/2 = 5.05
44
70 - 8 = 62; 62/2 = 31 which is the smaller number; 31 + 8 = 39 which is the other number.
There are 14 numbers - therefore, the median number is halfway between the seventh and eighth number. This is therefore 70.5.
An infinite number, there is no limit, there is an infinite number of numbers between .61 and .62, there is an infinite number between .61 and .611 .61 .6101 .61001 etc.
62.
44
(62 + 144) ÷ 2 = 103
It is (54 + 62)/2 = 116/2 = 58
Halfway between 42 and 82 is (42 + 82) ÷ 2 = 124 ÷ 2 = 62.
57.5
The median is 72.5, which is the number halfway between the two middle numbers when they are arranged in order.
39% of 62 = 62*39/100 = 24.18 = 24.2 to the nearest tenth
This question essentially is asking for the average of the two. Add them and divide by two: 35 + 89 = 124, and 124 / 2 = 62.
62 = 36 72 = 49 So 6 < sqrt(39) < 7
70 - 8 = 62; 62/2 = 31 which is the smaller number; 31 + 8 = 39 which is the other number.
70 - 8 = 62; 62/2 = 31. the other number is 31 + 8 ie 39
There are 14 numbers - therefore, the median number is halfway between the seventh and eighth number. This is therefore 70.5.