Q: What number needs to be added to 2999 to get 3?

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Any irrational number added to 0.5 will produce an irrational number.

7/10 must be added to 3/10 to make a whole number, 1.

Answer: 11It's a list of prime numbersQ:.....since when is 9 a prime number?Answer: 17It's not a list of primes, it's not a Fibonacci sequence. The only pattern I see is that the last number in the sequence gets a number added to it to produce the next number in the sequence, the number that's added doubles each time. E.g. 2+1 = 3 (1 is added)3+2 = 5 (1 is doubled = 2, then added)5+4 = 9 (2 is doubled = 4, then added)9+8 = 17 (4 is doubled = 8, then added)

The number required is 2/3 because 3*(2/3)+2*(3/2) = 5

When a natural number is multiplied by 1,000, the product is

Related questions

2999

2999 of them.

-3/4 - 3/7 = (-3×7)/(4×7) - (3×4)/(7×4) = -21/28 - 12/28 = -33/28 You need to add -33/28 = -1 5/28

number added by 3 equals 62 = 59Let x = the numberEquation: x + 3 = 62x + 3 - 3 = 62 - 3x = 59

Any irrational number added to 0.5 will produce an irrational number.

The answer would be 3+a right.

The number 2.

To me seems any amount of 3 added befor 1 makes that number always remain prime needs a heavy discution for above subject to be proved.

3 is added to every number 3 is added to every number

Any number of forces can be added.. The 3-D system does not limit the number of forces, only their dimensionality.

1

Any irrational number will do.