3
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
1, 3, 9 and 27.
an exact divisor of a number is one that leaves no remainder (a remainder of zero)--example: 27 divided by 3 is 9 but 27 divided bt 4 is 6 remainder 3 so 4 is not an exact divisor of 27 but 3 is
Check 9 out.
An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 27 is an odd number.
9
Because 3 divides evenly into 27 with no remainder.
3 This is because 24 is the highest number below 27 that can be divided into six without a remainder. 27 - 24 is 3, therefore the remainder is 3
3 divides 81 without remainder (3*27 = 81) so 3 is a factor of 81. 3 cannot be divided without remainder by any number other than 1 and 3 itself, so 3 is a prime. Combining the two statements, 3 is a prime factor of 81.
The number is 9.
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
1, 3, 9 and 27.
How about 27
' 1 ' is their only common factor.
an exact divisor of a number is one that leaves no remainder (a remainder of zero)--example: 27 divided by 3 is 9 but 27 divided bt 4 is 6 remainder 3 so 4 is not an exact divisor of 27 but 3 is
13 does not divide into 27 so the question makes no sense.
Divide the number by 5, and the remainder in that division is the 'ones' (50) digit. Take that quotient (without the remainder) and divide by 5. The remainder is the 'fives' (51) digit. Continue dividing until you have zero, with a remainder and that will be the leftmost digit. Example 27 (base ten) to base 5: 27 / 5 = 5, remainder 2 5 / 5 = 1, remainder 0 1 / 5 = 0, remainder 1 so 102 (base 5) is the same as 27 (base 10). You can check: 1 is in the (52=25) place, and the 2 is in the 'ones' place. So (1*25) + (0*5) + (2*1) = 27