5 times 20
105-5
10*10
23 + 77
34 + 66
27 + 73
38 + 62
11 + 89
32 + 68
54 + 46
there are probably others....this is all i can think of right now
100
5050
62.5 and 37.5
28
100 and 100 can add to 200 50, 50, 50, and 50 can add to 200 8 25s can add to 200 20 10s can add to 200
36 and 64
100
103
5050
53+47
62.5 and 37.5
36 + 64 = 100 (6x6) + (8x8)
28
50
-99
125
Let the five consecutive numbers be represented as n-2, n-1, n, n+1, and n+2. The sum of these numbers can be expressed as (n-2) + (n-1) + n + (n+1) + (n+2) = 5n. Setting this sum equal to 100 gives us 5n = 100. Solving for n, we find n = 20. Therefore, the five consecutive numbers that add up to 100 are 18, 19, 20, 21, and 22.