Any multiple of 60 is divisible by 3, 4, and 5.
(Also by 1, 2, 6, 10, 12, 15, 20, 30, and 60.)
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
Divisible by 5
76 is divisible by some of those numbers, but not all of them. 76 is an even number that ends in 6. It is divisible by 2. The sum of the digits of 76 (13) is not evenly divisible by 3. 76 is not divisible by 3. 4 times 19 is 76. 76 is divisible by 4. Only numbers that end in 0 and 5 are divisible by 5. 76 is not divisible by 5. 6 and 9 do not divide evenly into 76, so 76 is not divisible by 6 and 9. Only numbers that end in 0 are divisible by 10. 76 is not divisible by 10. Of the numbers listed, 76 is only divisible by 2 and 4.
268 is divisible by 2 and 4 the rest of the numbers 268 is not divisible by with a whole number being the dividend.
There are infinitely many numbers divisible by 5 and 4. 680 is one of them.
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
4 is not divisible by any 3-digit number. Nor are 5, 11 or 3. The smallest positive numbers that is divisible by 4, 5, 11 and 3 is 660.
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9
Divisible by 5
The numbers divisible by 4 and 5 are the numbers that are divisible by 20. Then, you should get the following multiples of 20: 20, 40, 60, 80, ...
76 is divisible by some of those numbers, but not all of them. 76 is an even number that ends in 6. It is divisible by 2. The sum of the digits of 76 (13) is not evenly divisible by 3. 76 is not divisible by 3. 4 times 19 is 76. 76 is divisible by 4. Only numbers that end in 0 and 5 are divisible by 5. 76 is not divisible by 5. 6 and 9 do not divide evenly into 76, so 76 is not divisible by 6 and 9. Only numbers that end in 0 are divisible by 10. 76 is not divisible by 10. Of the numbers listed, 76 is only divisible by 2 and 4.
Multiples of 60.
As these numbers have no common factors then any number divisible by 3, 4 & 5 is also divisible by (3 x 4 x 5) = 60. The answer is thus 240.
no.. heres a trick: if you add together the numbers (5+2+4) and that answer equals a number that is divisible by 3 then the number is divisible by three 5+2+4=11 11 is not divisible by 3 therefore, 524 is not divisible by 3
None of the numbers you listed are evenly divisible by 1000.
No, but I suspect you want to know if 186624 is divisible by those numbers. Out of that list, 186624 is divisible by all but 5.
Prime numbers are only divisible by 1 and itself... so no prime number can be divisible by the numbers you listed.