Numbers that are divisible by both 6 and 8 must be multiples of the least common multiple of 6 and 8, which is 24. Therefore, numbers that are divisible by both 6 and 8 are any multiples of 24. These numbers include 24, 48, 72, 96, and so on.
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Oh, isn't that a happy little question! When we're looking for numbers that are divisible by both 6 and 8, we're essentially looking for numbers that are multiples of the least common multiple of 6 and 8, which is 24. So, any number that is a multiple of 24 will be divisible by both 6 and 8. Just like painting, it's all about finding the right combination of colors to create something beautiful!
Well, honey, any number that is divisible by both 6 and 8 is also divisible by their least common multiple, which is 24. So, the numbers divisible by both 6 and 8 are multiples of 24. That's the tea, darling.
The LCM of 6 and 8 is 24, so all multiples of 24 are divisible by 6 and 8, that is 24, 48, 72, 96, etc.
2, 3, 4, 6, 8, 12 and 24
Four. 24 and its multiples.
To find the number of whole numbers between 1 and 500 that are divisible by 6 but not by 8, we need to find the numbers that are multiples of 6 and not multiples of 8. First, we find the multiples of 6 by dividing 500 by 6, which gives us 83 whole multiples. Next, we find the multiples of 8 by dividing 500 by 8, which gives us 62 whole multiples. To find the numbers that are multiples of 6 but not of 8, we subtract the common multiples of 6 and 8, which is 24, from the total multiples of 6, resulting in 83 - 24 = 59 whole numbers between 1 and 500 that are divisible by 6 but not by 8.
Oh, dude, so like, numbers divisible by 6 are any numbers that can be divided by 6 without leaving a remainder. So, like, 6, 12, 18, 24, and so on are all divisible by 6 because 6 goes into them evenly. It's like the cool kid at the math party, just dividing everything effortlessly.
No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9