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46, 51, 57, 64

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What numbers would you like to be missing?

Whatever numbers you specify, I can give you a formula for the general term of the pattern so that the numbers already specified, and the wanted numbers appear for the terms 1, 2, ..., n

However, the pattern given looks like it is: 36, 37, 39, 42, w, x, y, z, 72, 81, 91, 102, for which the simplest formula for the general term is t{n} = (x² -x + 72)/2 which means the missing terms t{5-8} are:

w = t5 = (5² - 5 + 72)/2 = 46

x = t6 = (6² - 6 + 72)/2 = 51

y = t7 = (7² - 7 + 72)/2 = 57

z = t8 = (8² -8 + 72)/2 = 64

The formula is derived from the fact that the difference between one term and the next is one more than the difference between the previous term and that term:

t2 = t1 + 1

t3 = t2 + 2 = t2 + 1 + 1

t4 = t2 + 3 = t2 + 2 + 1

→ t5 = t4 + 3 + 1 = t4 + 4 = 42 + 4 = 46

→ t6 = t5 + 4 + 1 = t5 + 5 = 46 + 5 = 51

→ t7 = t6 + 5 + 1 = t6 + 6 = 51 + 6 = 57

→ t8 = t7 + 6 + 1 = t7 + 7 = 57 + 7 = 64

→ t9 = t8 + 7 + 1 = t8 + 8 = 64 + 8 = 72

and the sequence continues.

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8y ago

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Related Questions

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102 = 32 + 34 + 36


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To find the missing number in the sequence 16, 4, 12, 36, 9, 27, 44, 11, we can look for a pattern. The first set of numbers appears to alternate between two sequences: the first sequence (16, 12, 9, 44) and the second sequence (4, 36, 27, 11). Following this pattern, the missing number, which follows the last number in the second sequence (11), should be 33. Thus, the missing number is 33.


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You may mean: 32+34+36 = 102


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