There are infinitely many possible answers.
Let A be any number in the interval (0, sqrt(200)] = (0, 14.142] approx.
and let B = 200/A so that A <= B
Then A*B = A*200/A = 200.
Since A was an arbitrary real number in the given range, there are infinitely many possible values for A and so infinitely many pairs.
Next, it is possible, similarly, to generate triplets, quartets, ... n-tuples, such that they multiply to 200.
It is a prime number.
8 X 8
How about: 2*16 = 32 as an example
Try: 2 times 0.99 = 1.98
The product of the GCF and LCM of a pair of numbers is equal to the product of the numbers.
It is a prime number.
8 X 8
49*2
3.14 times 200 is equal to 628. This can be calculated by multiplying 3.14 by 200. In this multiplication, you are essentially scaling the value of 3.14 by a factor of 200. The result, 628, is the product of this multiplication operation.
Factors
How about: 2*16 = 32 as an example
Try: 2 times 0.99 = 1.98
2 + 7 + 41 = 50
100*2=200
The product of the GCF and LCM of a pair of numbers is equal to the product of the numbers.
As far as i know its 2*13=26
1 x 22, 2 x 11.