There are two ways to solve this, the first is known as combination and is far easier. so,
a + b = 75
a - b = 13
add up both equations vertically. There are 2 a's, the b's cancel out, and the sum becomes 88.
2a = 88
a = 44
now that we have the value of a, plug that value into one of the two equations and u will c that the value is 31.
so 44 and 31
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The sum of all prime numbers between 60 and 75 is 272
try 11 & 14. 11 + 14 = 25 11sqd = 121 14sqd = 196 196-121 = 75!!!
There are eight pairs of numbers divisible by three that sum to 150, and 75 is also divisible by three, so: sum = 17 * 75 = 750 + 525 = 1275
Let's represent the two consecutive numbers as x and x+1. The sum of these two numbers is x + (x+1) = 2x + 1. Given that the sum is 75, we have the equation 2x + 1 = 75. Solving for x, we find x = 37. Therefore, the two consecutive numbers are 37 and 38, and their sum is indeed 75.