There are two ways to solve this, the first is known as combination and is far easier. so,
a + b = 75
a - b = 13
add up both equations vertically. There are 2 a's, the b's cancel out, and the sum becomes 88.
2a = 88
a = 44
now that we have the value of a, plug that value into one of the two equations and u will c that the value is 31.
so 44 and 31
53 and 22..
try 11 & 14. 11 + 14 = 25 11sqd = 121 14sqd = 196 196-121 = 75!!!
The sum of all prime numbers between 60 and 75 is 272
There are eight pairs of numbers divisible by three that sum to 150, and 75 is also divisible by three, so: sum = 17 * 75 = 750 + 525 = 1275
Let's represent the two consecutive numbers as x and x+1. The sum of these two numbers is x + (x+1) = 2x + 1. Given that the sum is 75, we have the equation 2x + 1 = 75. Solving for x, we find x = 37. Therefore, the two consecutive numbers are 37 and 38, and their sum is indeed 75.
30 and 45
53 and 22..
The two numbers are 11 and 14. 11 + 14 = 25, 142 - 112 = 75
3.75 and .75 3.75 + .75 = 4.5 3.75 - 0.75 = 3
The sum of 75 and 75.
The sum of all prime numbers between 60 and 75 is 272
try 11 & 14. 11 + 14 = 25 11sqd = 121 14sqd = 196 196-121 = 75!!!
75 is LCM The numbers are 15 and 25 15 + 25 = 40 25 - 15 = 10 75 / 15 = 5 75 / 25 = 3
Since their difference is zero, they're the same number.Since they're the same number, each one is 1/2 of 150.Both numbers are 75 .
24 + 25 + 26 = 75
30 x 10 = 300. 75 + 75 = 150. Their difference is 150.
The sum is 75.