81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9
162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9
199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9.
1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9.
So 199 is the only one not divisible by 9.
No, 199 is not divisible by 9
There are 12 numbers between 100 and 199 that are divisible by eight: 104, 112, 120, 128, 136, 144, 152, 160, 168, 176, 184 and 192.
1, 3, 199, 597.
Testing the largest whole number less than 200, 199, we find that it is not evenly divisible by 2, 3, 5, 7, 11 or 13. Since the square root of 199 is between 14 and 15, there's no need to test any prime numbers higher than 14. Therefore, the answer is 198, since it is an even number, and all even numbers are composite numbers because they are divisible by 2. A composite number is the opposite of a prime number.
There are 199 multiples of 5 in that range. There are 128 multiples of 7 in that range. There are 28 numbers on both lists. 1000 - 299 = 701
19 divisible by 5, 14 divisible by 7. Of these, 3 divisible by both.
Here's a mathematical trick. Any number wholly divisible by 3 has the sum of its digits equal to 3 or a multiple of 3. 199 : 1 + 9 + 9 = 19....NOT divisible by 3 209 : 2 + 0 + 9 = 11....NOT divisible by 3 390 : 3 + 9 + 0 = 12....YES, this is divisible by 3 499 : 4 + 9 + 9 = 22....NOT divisible by 3 Note : 390 ÷ 3 = 130
Yes because 597/3 = 199
Not evenly. The answer would be 18 remainder 1.
No, it would be divisible by ten.
It is: 199+99 = 298
199 is a prime number; it has no composite factors.