4,5,14,15,24,25,34,35,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,64,65,74,75,84,85,94,95 = 36 out of 100 = 36%
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271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
262. Here's how:Let's look at 1 to 99, where 18 number contain a 9 digit. First there is 1 to 89, which 8 numbers contain the nine: {9,19,29,...89}, then all ten of the 90's have a 9, so that's 18. The next 8 groups, [101-199], [201-299] ... [801-899] follow this same pattern. and finally all 100 of the numbers [900 - 999] contain a 9.So it is 100 + (9 x 18) = 262This assumes you mean whole numbers only, as decimals or rationals would create an infinite set of numbers (unless you limited it to a certain number of decimal places)
First, divide by the amount of numbers (184 divide 4 = 46) and then find the numbers on either side. In this case, they are 43,45,47,49.
The first five whole numbers are: 01234. The first five natural numbers are: 12345.
To round numbers to the nearest whole percent on a calculator, you first divide the number by 100 to convert it to a decimal. Then, multiply the decimal by 100 to convert it back to a percentage. Finally, round the percentage to the nearest whole number. For example, if you have the number 78.56, you would first divide by 100 to get 0.7856, then multiply by 100 to get 78.56%, which rounds to 79%.