9
2
8
Slope: -3 Point: (4, -5) Equation: y = -3x+7
Given a set of points, (x1, y1), (x2, y2), etc. Take the absolute value of each point's x and y values, and replace those. Take the inverse point of each point, e.x. (x1, y1) -> (y1, x1) Apply the signs that correspond to the quadrant counterclockwise of the quadrant the point was in. e.x. (3, 5) is in the First Quadrant. The Second Quadrant is counterclockwise of the First, so we will have the x-value of the point negative: (-3, 5). Do that for all points.
If you mean point (2, 5) then it is in the 1st quadrant on the Cartesian plane
9
Quadrant 1(II) ; Top left. "
5
If you mean (5, 2) then it is in the 1st quadrant on the Cartesian plane
III
2
Depending how you read the graph it could be the 2nd quadrant anti-clockwise
-1
8
Slope: -3 Point: (4, -5) Equation: y = -3x+7
Given a set of points, (x1, y1), (x2, y2), etc. Take the absolute value of each point's x and y values, and replace those. Take the inverse point of each point, e.x. (x1, y1) -> (y1, x1) Apply the signs that correspond to the quadrant counterclockwise of the quadrant the point was in. e.x. (3, 5) is in the First Quadrant. The Second Quadrant is counterclockwise of the First, so we will have the x-value of the point negative: (-3, 5). Do that for all points.