All multiples of their lowest common multiple are multiple of all of them.lcm(2, 6, 8) = 2455 ÷ 24 = 2 r 7 → first multiple of 24 greater than 55 is 3 x 24 = 72101÷ 24 = 4 r 5 → last multiple of 24 less than 101 is 4 x 24 = 96→ the numbers 72 and 96 are multiples of 2, 6 & 8 between 55 and 101.
d = r + 6 now you make the equation relating what happened 6 yrs ago, remembering that then they were r-6 and d-6: dr = 2(r-6)(d-6) plug the first eqn into the second one and solve: r(r+6) = 2(r-6)(r) you can cancel an r, since r isn't 0! r+6 = 2(r-6) r=18 So Ricardo is 18 and his sis is 24.
100 ÷ 38 = 2 remainder 24
6/1 ( the fraction we need the equivelents of ) the answers : 12/2 18/3 24/4 30/5 36/6
Let a be the first of the three number and r the common ratio. Then a*ar*ar2 = a3r3 = 216 = 63 so that ar = 6 Also, a + ar + ar2 = 21 Substitute ar = 6 to give 6/r + 6 + 6r = 21 or 6 + 6r + 6r2 = 21r So that 6r2 - 15r + 6 = 0 or 2r2 - 5r + 2 = 0 2r2 - 4r - r + 2 = 0 or 2r*(r-2) - 1(r-2) = 0 or (2r-1)*(r-2) = 0 so r = 0.5 or r = 2 r = 0.5 gives the three numbers as being 12, 6, 3 and r = 2 gives 3, 6, 12.
They are 1 and 3
Greatest common factor of 12 and 18 and 24 is 6.
The factors for 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72.
6 times, with a remainder.
1 and 5
How about: 8 16 and 24
1,11,12,13,14,15,16,17,18,19,2,6,7,8,9,3,4,5, those r some of the factors between 10 and 20
1, 2, 3, 6, 17, 34, 51, 102 r .
All multiples of their lowest common multiple are multiple of all of them.lcm(2, 6, 8) = 2455 ÷ 24 = 2 r 7 → first multiple of 24 greater than 55 is 3 x 24 = 72101÷ 24 = 4 r 5 → last multiple of 24 less than 101 is 4 x 24 = 96→ the numbers 72 and 96 are multiples of 2, 6 & 8 between 55 and 101.
17 and 34's highest common factor is 17.
The factors of 30 are... 1, 2, 3, 5, 6, 10, 15, and 30
It is 48/2= 24 r 0 ^ 24/2= 12 r 0 | 12/2 = 6 r 0 | 6/2 = 3 r 0 | 3/2 = 1 r 1 | 1/2 = 0 r 1 | So your read it from 1 to 48 :D Enjoy