All multiples of their lowest common multiple are multiple of all of them.lcm(2, 6, 8) = 2455 ÷ 24 = 2 r 7 → first multiple of 24 greater than 55 is 3 x 24 = 72101÷ 24 = 4 r 5 → last multiple of 24 less than 101 is 4 x 24 = 96→ the numbers 72 and 96 are multiples of 2, 6 & 8 between 55 and 101.
d = r + 6 now you make the equation relating what happened 6 yrs ago, remembering that then they were r-6 and d-6: dr = 2(r-6)(d-6) plug the first eqn into the second one and solve: r(r+6) = 2(r-6)(r) you can cancel an r, since r isn't 0! r+6 = 2(r-6) r=18 So Ricardo is 18 and his sis is 24.
100 ÷ 38 = 2 remainder 24
6/1 ( the fraction we need the equivelents of ) the answers : 12/2 18/3 24/4 30/5 36/6
Let a be the first of the three number and r the common ratio. Then a*ar*ar2 = a3r3 = 216 = 63 so that ar = 6 Also, a + ar + ar2 = 21 Substitute ar = 6 to give 6/r + 6 + 6r = 21 or 6 + 6r + 6r2 = 21r So that 6r2 - 15r + 6 = 0 or 2r2 - 5r + 2 = 0 2r2 - 4r - r + 2 = 0 or 2r*(r-2) - 1(r-2) = 0 or (2r-1)*(r-2) = 0 so r = 0.5 or r = 2 r = 0.5 gives the three numbers as being 12, 6, 3 and r = 2 gives 3, 6, 12.
They are 1 and 3
Greatest common factor of 12 and 18 and 24 is 6.
The factors for 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, and 72.
1 and 5
How about: 8 16 and 24
6 times, with a remainder.
1,11,12,13,14,15,16,17,18,19,2,6,7,8,9,3,4,5, those r some of the factors between 10 and 20
1, 2, 3, 6, 17, 34, 51, 102 r .
17 and 34's highest common factor is 17.
The factors of 30 are... 1, 2, 3, 5, 6, 10, 15, and 30
All multiples of their lowest common multiple are multiple of all of them.lcm(2, 6, 8) = 2455 ÷ 24 = 2 r 7 → first multiple of 24 greater than 55 is 3 x 24 = 72101÷ 24 = 4 r 5 → last multiple of 24 less than 101 is 4 x 24 = 96→ the numbers 72 and 96 are multiples of 2, 6 & 8 between 55 and 101.
It is 48/2= 24 r 0 ^ 24/2= 12 r 0 | 12/2 = 6 r 0 | 6/2 = 3 r 0 | 3/2 = 1 r 1 | 1/2 = 0 r 1 | So your read it from 1 to 48 :D Enjoy