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5*sin(30) = 2.5 metres.

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13y ago

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What rise does a 6 degree angle give over a 12.5M length?

A rise of 1.31 metres.


What rise will a 1 degree angle give over 13 meters?

The rise over the distance is equal to the tangent of the angle Since tan (1 degree) = .0174 then the rise is .0174x13 = 0.227 meters ( 227 mm)


What rise does a 6 degree angle give over 12.5?

Approx 1.31 units.


What rise does a 22 degree angle give over 7.5 feet?

3.03 feet (rounded)


How much fall in a 2 degree roof over 4 metre?

To determine the fall (or slope) of a 2-degree roof over a 4-meter span, you can use the formula for rise: rise = distance × tan(angle). For a 2-degree angle, the rise is approximately 0.07 meters (or 7 centimeters) over 4 meters. Therefore, the fall over a 4-meter length at a 2-degree slope is about 7 centimeters.


What rise does a 6 degree angle give over 12.5m?

Use the following formula:Rise = run * tan (x)= 12.5 m * tan (6o)= 12.5 M * 0.1051approx. 1.31 m


How many inches of rise is there over 48 inches at a 15 degree angle?

rise/run = tangent 15 degrees rise = tan(15) x 48 = 12.86 inches


How much 1 degree rise in 100 feet?

The rise is calculated as the horizontal run distance times the tangent of the angle (tan angle = rise/run). Since tan 1 degree is 0.0175 the rise is 100 x .0175 = 1.75 feet


Why is there not an angle angle angle theroem?

Because angle angle angle does not necessarily give rise to congruent triangles - they can be similar, but non-congruent.


What is the tangent of a 45 degree angle?

It is equal to 1 (one). A 45 degree angle produces a vertical rise equal to the horizontal run, producing an isosceles right triangle with a hypotenuse of (sq rt 2)*a where a is the height/side. Opposite over adjacent = a/a = 1.


How much fall in a 2 degree roof over 2 metres?

To calculate the fall (or slope) of a roof, you can use the formula for slope, which is rise over run. For a 2-degree angle over a horizontal distance of 2 metres, you can use the tangent function: ( \text{rise} = \text{run} \times \tan(\text{angle}) ). Thus, the fall would be approximately ( 2 , \text{m} \times \tan(2^\circ) ), which results in about 0.07 metres, or 7 millimetres.


How much fall in 3 degree' roof over 1.8 metres?

To calculate the fall of a roof with a 3-degree pitch over a distance of 1.8 meters, you can use the formula for rise, which is ( \text{rise} = \text{run} \times \tan(\text{angle}) ). First, calculate ( \tan(3^\circ) ) which is approximately 0.0524. Therefore, the rise over 1.8 meters is ( 1.8 \times 0.0524 ), resulting in a fall of approximately 0.0943 meters, or about 9.43 centimeters.