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A square root can belongs to the following subsets:

  • complex numbers
  • real numbers
  • rational numbers
  • integers
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Q: What subset of numbers does a square root belong to?
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Related questions

Which subset does the square root of 2 belong in?

They are irrational numbers


What sets of numbers does the square root of 10 belong to?

Irrational Numbers which are a subset of Real Numbers which are a subset of Complex Numbers ...


The square root of a value is called an imaginary or complex number?

Not necessarily. The square root of 4 are +/- 2 which are Real numbers, NOT imaginary. Although, since the Reals are a subset of Complex numbers, the above roots would belong to the Complex numbers.


Is the square root of 225 a subset of the irrational numbers?

The square root of 225 is 15, which is NOT an irrational number.


What is the subset of the square root of 2?

The empty set is a subset.


What set of numbers does the square root of 121 belong to?

The square root of 121 is rational, an integer, and a natural number.


Which subset does the square root of 13 belong in?

It belongs to many many subsets including: {sqrt(13)}, The set of square roots of integers The set of square roots of primes The set of square roots of numbers between 12 and 27 {3, -9, sqrt(13)} The set of irrational numbers The set of real numbers


What set or sets does the square root of 30 belong to?

real numbers, irrational numbers, ...


Where does the square root of 3 belong?

It belongs in the irrational group of numbers.


What set of numbers does the square root of 6 belong?

Root 6 is an irrational [real] number.


Is the square root of -4 irrational?

The square root of -4 is not irrational, it is imaginary. Irrational numbers are numbers that cannot be expressed as a fraction, like the square root of 2. Irrational numbers, however, are a subset of real numbers. The square root of -4 however, is not even a real number because no real number, when squared, gives -4. Therefore the square root of -4 is an imaginary number.In calculus, the root is expressed as 2i where iis the square root of -1.


What is the domain of 1 divided by the square root of x plus 8?

Any subset of the real numbers which excludes the value -8