0
Sum = addition
Difference = subtraction
Say your first number is x and your second number is y. So:
x+y = 10 and x-y = 20
Solve for one variable for one of the above equations and substitute that variable into the other equation:
x = 10-y
(10-y)-y = 20
10-2y = 20
Get y by itself:
-2y = 20-10
-2y = 10
Solve for y:
-2y/-2 = 10/-2
y = -5
To solve for x:
x = 10-y
x = 10-(-5)
x = 10+5
x = 15
Therefore, the two numbers you are looking for are -5 and 15.
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∙ 14y ago
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What two numbers have the sum of 12 and the difference of 8?
The two numbers are 10 and 2
What is the sum of 40 and a difference of 10?
The two numbers are 25 and 15
I am the ratio of the sum of two numbers whose product is 21 to their difference. what ratio am I?
3 & 7? Sum 10, difference 4 so ratio 5:2 or 1 & 21? Sum = 22, difference 20 so ratio 11:10
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2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
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What two numbers have the sum of 12 and the difference of 8?
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The two numbers are 5 and 15. 5 + 15 = 20. 15 - 5 = 10.
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It is: (20*10)-(20+10) =170
I am the ratio of the sum of two numbers whose product is 21 to their difference. what ratio am I?
3 & 7? Sum 10, difference 4 so ratio 5:2 or 1 & 21? Sum = 22, difference 20 so ratio 11:10
The sum of two numbers is 20 and their difference 4 Find the numbers?
8 & 12
What two numbers have a sum of 20 and a difference of 8 what are the two numbers?
It is 14 and 6.
Two numbers have a sum of 40 the difference is 10 what are the two numbers?
2 Numbers are a and b. We have( a>b) a+b=40(1) and a-b=10(2) a=10+b( from 2. Subtracts both side by b) => 10+b+b=40 (from 1. Substitute a with 10+b) => 10+2b =40 => 2b =30 => b =15 =>a=10+15=25 => a=25 b=15.
The sum of two numbers is 10 their product is 20 the sum of reciprocals is what?
It is 0.5
