They are: 90+91+92 = 273
Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.
Divide the total by 1.2 Example: If the inflated total is $273, the original price was 273/1.2 = $227.50 .
To find out how many times 12 goes into 273, you would perform division. Divide 273 by 12 to get the quotient, which is 22 with a remainder of 9. Therefore, 12 goes into 273 a total of 22 times.
It is 273/1It is 273/1It is 273/1It is 273/1
89, 91, and 93
The numbers are 89, 91 and 93 and 90, 91 and 92
They are: 90+91+92 = 273
Divide the sum of the three consecutive odd integers by 3: -273 /3 = -91. The smallest of these integers will be two less than -91 and the largest will be two more than -91, so the three consecutive odd integers will be -89, -91, and -93.
91+31+151=273
The numbers one and three go into 273 and six evenly.
Suppose the smallest number is x. Then the six numbers are x, x+1, x+2, x+3, x+4 and x+5. Their sum is 6x+15 which is 273. So 6x = 273-15 = 258 So x = 258/6 = 43. The six numbers are 43, 44, 45, 46, 47 and 48.
7 x 39 = 273 13 x 21 = 273
3 + 131 + 139 = 273 73 + 97 + 103 = 273 37 + 43 + 193 = 273
3 and 91 multiplied together make 273
1, 3, 7, 13, 21, 39, 91, 273.
Yes. 273 is evenly divisible by three.