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Let 'n' be the first odd number,.

Then n+ 2 & n + 4 are the second and third odd number.

Hence

n + (n+2) + ( n + 4) = 339

Add

3n + 6 = 339

3n = 333

n = 111

n + 2 = 113

n + 4 = 115

Hence the three odd consecutive numbers are 111,113 & 115.

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lenpollock

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βˆ™ 2023-04-02 10:44:18
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βˆ™ 2009-05-13 09:02:04

average is 113 so 111, 113 and 115

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Q: What three consecutive odd numbers that have the sum of 339?
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