To find three numbers that multiply to 210, we need to consider the prime factorization of 210, which is 2 x 3 x 5 x 7. From this, we can see that the three numbers are 2, 3, and 35, as 2 x 3 x 35 = 210. These numbers are the prime factors of 210 and when multiplied together, they result in the given product.
221
2 and 210
643
22998
221
210
The four smallest prime numbers are 2, 3, 5 and 7. Multiply them together. You'll get 210.
2x25
To find three numbers that multiply to 210, we need to consider the prime factorization of 210, which is 2 x 3 x 5 x 7. From this, we can see that the three numbers are 2, 3, and 35, as 2 x 3 x 35 = 210. These numbers are the prime factors of 210 and when multiplied together, they result in the given product.
Start by factoring each of the numbers. Then eliminate duplicate factors, and multiply together whatever factors are left. 42=2x3X7 30=2x3x5 Since the 2 and 3 are duplicated, eliminate the duplications, and multiply 2X3X5X7=210. Answer: 210
Because the four smallest prime numbers are 2, 3, 5, and 7. If you multiply these four together you get 210 (which makes 210 the smallest number divisible by four unique prime numbers).
2 and 210
210
643
22998
First, you make a factor tree for both 36 and 210 and find the prime factorization of both numbers.36: 2x2x3x3210:2x3x5x7Then, you circle the numbers that appear in both factorizations. (I'll make them bold.)36: 2x3x2x3210: 2x3x5x7Lastly, you multiply the 2 numbers that you circled together (only one pair of the 2 numbers; don't multiply 2x3x2x3, just 2x3).2x3=6.The GCF of 36 and 210 is 6.