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How many hours before midnight in 3 hours?
If the time now is T hours (on a 24 hour clock), then the answer is mod(21 - T, 24) hours.
If It's nine o'clock right now what time was it eight hours ago?
1 o'clock
How long is 70 hours?
2 days and 22 hours
9 large pipes drains a pond in 8 hours and 6 small pipes drains a pond in 16 hours How long will 3 large pipes and 5 small pipes take to drain a pond?
If 9 large pipes take 8 hours to drain the pond, then 1 large pipe would take 8*9=72 hours. large_pipe_rate = (1/72) pond/hour Since 6 small pipe drain the pond in 16 hours, then 1 small pipe would take 6*16 = 96 hours. small_pipe_rate = (1/96) pond/hour Now we can calculate using: rate * time = work done In this case, we have two rates, but a common time, so we will have: (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 Plug in the values we know and solve for "time": (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 (3 * (1/72))*time + (5 * (1/96))*time = 1 (3/72)*time + (5/96)*time = 1 (3/72 + 5/96)*time = 1 time = 1/(3/72 + 5/96) time = 1/.09375000 time = 10.66666667 Answer: 3 large pipes and 5 small pipes could drain the pond in 10 and 2/3 hours (which is 10 hours and 40 minutes). ----------------------- The other answers disagree with me. I would like you to get this problem correct, and to be honest, I'd like the points for showing the correct way to do it. So, I'll take a moment to show you why the other answers don't even make sense. Consider if all 8 pipes were large. We know that *9* large pipes could drain the pond in 8 hours. With a little calculation, we can see that 8 large pipes could drain it in 9 hours: 8 * (1/72) * time = 1 (1/9) * time = 1 time = 9 hours If all 8 pipes were small, then it would take: 8 * (1/96) * time = 1 (1/12)* time = 1 time = 12 hours So we **know** it will be somewhere between 9 and 12 hours. Certainly NOT 16 hours. Go back to the problem statement and notice that 6 small pipes can drain the pond in 16 hours. The other answers claim that 5 small pipes + 3 large pipes also take 16 hours. Therefore, their claim is that: 6 small pipes = 5 small pipes + 3 large pipes In other words, by removing 1 of the 6 small pipes and adding 3 large ones, the drain time remains at 16 hours: 1 small pipe = 3 large pipes Nonsense. Bottom line: 3 large + 5 small will take 10 hours and 40 minutes.
If the time is now 1030 pm and the clock now says 430 am because of a power outage then how long was the power outage taking into consideration that the clock resets to 1200 am?
I believe 4 hours and 30 minutes.
