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To find the factor pairs of 176, you first need to break it into its prime factors. It is clearly even so we can divide by 2, to get 88. This is known from the times tables to be 8x11. Thus the prime factors of 176 are 2, 2, 2, 2 and 11.

To find factor pairs you simply multiply some of these numbers together, and then multiply the rest together as the second number. For example we have:

2 and 2x2x2x11 (88)

2x2 (4) and 2x2x11 (44)

2x2x2 (8) and 11

There is also 1 and 176.

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13y ago

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