Well, well, well, aren't we feeling all mathematical today? If one angle is 28 degrees in a right triangle, the other acute angle must be 62 degrees (90 - 28 = 62). As for the right angle, it's a whopping 90 degrees. Math can be a real trip sometimes, can't it?
47 X 62= 2914
1/2*base*8 = 48 Multiply both sides by 2 and then divide both sides by 8: Base = 12 cm An isosceles triangle is made from two right angle triangles. So use Pythagoras' theorem to find the hypotenuse which will be one of the isosceles equal sides: 82+62 = 100 and the square root of this is 10 Use the tangent ratio to find the base angle: tan = opp/adj => tan = 8/6 = 53.13010235 or 53 degrees to the nearest degree Therefore: The isosceles triangle has two equal sides of 10 cm and a base of 12 cm. It has two equal base angles of 53 degrees and a vertex angle of 74 degrees.
1.8807 is. (rounded)
Sin(62 deg) = 0.8829Sin(62 deg) = 0.8829Sin(62 deg) = 0.8829Sin(62 deg) = 0.8829
A scalene triangle and the other angle is 47 degrees
They are both acute angles because they are less than 90 degrees and the 3rd angle is 71 degrees which is also an acute. The triangle is a scalene triangle.
It is a scalene triangle and the 3rd angle is 47 degrees
I assume you mean a TRIANGLE. The angles in a triangle will sum up to 180 degrees. So sum your two angles and subtract that from 180.
It is an acute scalene triangle
The other 2 angles are c 62 and 90 degrees
The 3rd angle will measure 180 -77 -62 = 41 degrees
78 degrees I believe.
That will depend on the shape but if it's a triangle then the missing angle is 54 because there are 180 degrees in a triangle.
The sum of a triangle's angles must always equal 180, so 54+62=116. 180-116=64. The third angle is a 64 degree angle.
i think it is 71 . i think because you can add 62+47 =109-180 so put it like this 108 -109=71
The angles must add up to 180o Let the missing angle be x so, x + 62o + 47o = 180o x = 71o