39 and 84.
120 and 3.
eight times two equals 16
The two numbers are 50 and 63. Their sum is 113 and they have a difference of 13.
Suppose the smaller number is x, then the bigger number is x+7 Their sum is 123 ie x + (x+7) = 123 or 2x + 7 = 123 or 2x = 123 - 7 = 116 so that x = 58 and then x+7 = 65 The two numbers are 58 and 65
There is no such pair.
two numbers which are equal to 123:123 + 0122 + 1121 + 2120 + 3 ...
They are 61+62 = 123
When multiplied together, 3 and 41 equal 123.
120 and 3.
65 + 58 = 123 65 - 58 = 7 The two numbers are therefore 58 and 65.
To find two numbers where one subtracts the other to equal 123, you can express it as ( x - y = 123 ). For example, if you let ( y = 0 ), then ( x ) would equal 123. Alternatively, if ( x = 200 ), then ( y ) would be ( 200 - 123 = 77 ). There are infinitely many pairs of numbers that satisfy this equation.
122 and 123.
84 + 39 = 123 84- 39 = 45 84 + 39 = 123 84- 39 = 45
eight times two equals 16
The two numbers are 50 and 63. Their sum is 113 and they have a difference of 13.
Suppose the smaller number is x, then the bigger number is x+7 Their sum is 123 ie x + (x+7) = 123 or 2x + 7 = 123 or 2x = 123 - 7 = 116 so that x = 58 and then x+7 = 65 The two numbers are 58 and 65
700