120 and 3.
Suppose the smaller number is x, then the bigger number is x+7 Their sum is 123 ie x + (x+7) = 123 or 2x + 7 = 123 or 2x = 123 - 7 = 116 so that x = 58 and then x+7 = 65 The two numbers are 58 and 65
eight times two equals 16
The two numbers are 50 and 63. Their sum is 113 and they have a difference of 13.
There is no such pair.
two numbers which are equal to 123:123 + 0122 + 1121 + 2120 + 3 ...
They are 61+62 = 123
When multiplied together, 3 and 41 equal 123.
120 and 3.
65 + 58 = 123 65 - 58 = 7 The two numbers are therefore 58 and 65.
122 and 123.
84 + 39 = 123 84- 39 = 45 84 + 39 = 123 84- 39 = 45
eight times two equals 16
Suppose the smaller number is x, then the bigger number is x+7 Their sum is 123 ie x + (x+7) = 123 or 2x + 7 = 123 or 2x = 123 - 7 = 116 so that x = 58 and then x+7 = 65 The two numbers are 58 and 65
The two numbers are 50 and 63. Their sum is 113 and they have a difference of 13.
700
11.5 +/- sqrt(7.25) = 8.8074 and 14.1926 (to 4 dp)