If we call the two numbers a and b then ab = 140 and a + b = 31. Solving the second equation for b results in b = 31 - a. Then substituting this back into the first equation results in:
a(31 - a) = 140
Distribute and subtract 31 from both sides:
-a2 + 31a - 140 = 0
Use the quadratic formula to solve for a:
a = about 5.488 or 25.516
Then plug this numbers back into an original equation (such as a + b = 31) and solve for b. If a is 5.488 then b ends up being 25.516. If a is 25.516 then b ends up being 5.488.
So the two numbers are about 5.488 and 25.516. (The exact forms are (1/2)(31 - sqr(401)) and (1/2)(31 + sqr(401)) The plus or minus in the quadratic formula takes care of what both numbers will be, so you don't have to substitute back if you find both possible values for a.)
-144
-171
70*2
15 and 10 if you multiply them. 140 and 10 if you add them. 160 and 10 if you subtract them. 1500 and 10 if you divide them.
There are infinitely many pairs. The simplest is 1 and 140.
-144
-171
2840
280
70*2
15 and 10 if you multiply them. 140 and 10 if you add them. 160 and 10 if you subtract them. 1500 and 10 if you divide them.
There are infinitely many pairs. The simplest is 1 and 140.
To solve this problem, we are looking for two numbers that multiply to 150 and add to -19. Letβs break it down: Product of the two numbers: The two numbers should multiply to give 150. Sum of the two numbers: The same two numbers should add up to -19.
There are no two real numbers that do, but the complex numbers (2 + i) and (2 - i) will.If you want two numbers that multiply to negative 5 and add to positive 4 then: -1 and 5If you want two numbers that multiply to negative 5 and add to negative 4 then: 1 and -5
45
The two numbers that multiply to -72 and add to -29 are approximately 3.57 and -32.57.
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