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Oh, what a happy little math problem we have here! Let's see, the numbers we're looking for are 6 and 4. When you multiply them, you get 24, and when you add them, you get 10, not 1. But that's okay, mistakes are just happy accidents in the world of numbers!
Let A,B be any number (in this case, the numbers won't be real)
A x B = 24
A + B = 1
Solve for A or B in either equation, and plug that value into the other equation.
A + B = 1
A = 1 - B
AB = 24
(1-B)B = 24
B - B2 - 24 = 0
(-1)(-B+B2+24)=0
B2-B+24=0 <--- you have a polynomial, which cannot be factored, so use the quadatric formula
B = (1±√(1-96))/2
B = 1/2 ± (√95)i/2
You can plug B back into either equation to find what A is, but in this case one number will the the positive 1/2 + (√95)i/2 and the other will be the negative 1/2 - (√95)i/2 version of the answer.
Check your work:
(1/2 + (√95)i/2)(1/2 - (√95)i/2) = 24
(1/2 + (√95)i/2) + (1/2 - (√95)i/2) = 1
The answer is:
(1/2 + (√95)i/2) and (1/2 - (√95)i/2)