What two numbers multiply to equal -1200 and add to equal -10 and is there a solution?

Answer 1

-1210

Answer 2

Basically you have two equations: xy = -1200 x + y = -10 Step 1: Solve one of these equations, for one of the variables (I suggest the first): xy = -1200 (xy)/x = (-1200)/x Divide both sides by x to get y by itself. y = -1200/x Step 2: Substitute the value of that variable into the other equation so that you are only dealing with one variable. x + -1200/x = -10 Step 3: Solve for X. x ( x - 1200/x) = (-10)x Multiply both sides by x to get rid of the fraction. x2 - 1200 = -10x x2 + 10x - 1200 = 0 Because this is a quadratic equation put all value on one side. (x + 40)(x - 30) = 0 Factor out the quadratic. x = - 40 or x = 30 Step 4: Plug this value(s) back into either original equations. x + y = -10 -40 + y = -10 y = 30 Step 5: If there is a second potential value, plug that back into the original equation. x + y = -10 30 + y = -10 y = -40 (This is the same answer as before just with x and y reversed so we can ignore) Step 6: Test answer. xy = -1200 (-40)(30) = 1200 TRUE x + y = -10 -40 + 30 = -10 TRUE -40 and 30 is the answer.

Answer 3

Oh, dude, you're hitting me with some math here! So, the numbers you're looking for are -40 and 30 because -40 multiplied by 30 equals -1200 and -40 plus 30 equals -10. Yeah, there's a solution, but like, don't expect me to be excited about it or anything.

Answer 4

600×2=1200