1/a + 1/b = b/ab + a/ab = (b+a)/ab So, the answer to your question is 32/48 or 2/3
Find two numbers if their sum is 64 and their difference is 12. The two numbers are
32 - 22 + 10 32 + 22 = 54
23 and 32
Let's denote the two numbers as x and y. We know that the sum of the two numbers is 4, so we can write the equation x + y = 4. We also know that their product is -32, so we can write the equation xy = -32. By solving these two equations simultaneously, we can find the two numbers. The numbers are 8 and -4.
It is: 29+3 = 32
Two prime numbers that have a sum of 32 could be 13 + 19 or 29 + 3.
29+3 = 32 and 29+7 = 36
21 and 32
That isn't possible. The sum of three odd numbers will always be odd. You can make the sum of 3 prime numbers equal to 32 if one of them is 2 (which is not odd).
0,13,19
2, 13, and 17, but 2 is not a prime number
The sun of two num is 32 and the difference is 10. What are the numbers?
The numbers are: 32+29 = 61
No. Not even close. Examples: 4+4=8 8+8=16 16+16=32 . . .4, 8, and 16 are not prime numbers.
Except for 2, all other prime numbers are odd. The sum of any two odd numbers is even. Therefore, the prime number 2 will evenly divide the sum of any other two prime numbers. Here are some examples to illustrate this: 3 + 5 = 8 which is evenly divisible by 2 13 + 19 = 32 which is evenly divisible by 2 43 + 47 = 90 which is evenly divisible by 2
28 and 32