(10-2)-1 = 7 whole numbers
7, 8 and 9 are whole numbers.
8, square = 64 9, square = 81 10, square = 100 11, square = 121 12, square = 144 13, square = 169 14, square = 196 Thus the whole numbers would be 8, 9, 10, 11, 12, 13 and 14.
Assuming the question is meant to be about the whole numbers between which root 98 lies, the answers are: -10 and -9, and 9 and 10.
10 and a half, being between the whole numbers 10 and 11, can't be a whole number itself.
(10-2)-1 = 7 whole numbers
You know that sum of the first n whole numbers is n(n+1)/2. ( it is the same as the first n natural numbers since the zero does not add anything) So lets say you want the sum of all the whole numbers between 3 and 10. ( I made it easy to illustrate the idea.) The sum of the whole numbers between 0 and 3 is 3(4)/2=6 The sum of the whole numbers between 0 and 10 is 10(11)/2=55 So the sum of the whole numbers between 3 and 10 is the (sum of the whole number between 0 and 10) -(sum of whole numbers between 0 and 3) which is 55-6=49 So in general, for whole numbers m and n with m
7, 8 and 9 are whole numbers.
swer in a 4x4 magic squares with 10-=25 numbers in each column?
8, square = 64 9, square = 81 10, square = 100 11, square = 121 12, square = 144 13, square = 169 14, square = 196 Thus the whole numbers would be 8, 9, 10, 11, 12, 13 and 14.
56789
Assuming the question is meant to be about the whole numbers between which root 98 lies, the answers are: -10 and -9, and 9 and 10.
10 and a half, being between the whole numbers 10 and 11, can't be a whole number itself.
There are no prime numbers in between these numbers. The only whole number between them is 6
Only 5 whole numbers:6, 7, 8, 9, and 10.
There are 10 whole numbers in 10 to 19.
The square root of 89 is approximately 9.4 so 9 and 10 are the closest whole numbers. You could also notice that 9 squared is 81 and 10 squared is 100 which are the closest perfect squares to 81.