By Pythagoras,
Hypotenuse2 = Base2 + Perpendicular2
So perpendicular2 = Hypotenuse2 - Base2 = (H + B)*(H - B)
= (a + b + a - b) *(a + b - a + b) = 2a*2b = 4ab
So perp = sqrt(4ab) = 2*sqrt(ab)
Starting with an equilateral triangle of side 2, dropping a perpendicular from one vertex to the opposite base creates two equal right angled triangles with hypotenuse of length 2, base length 1 and height of length √(22 - 12) = √3 which is the longer leg of the 30-60-90 triangle. Thus the ratio of longer_leg : hypotenuse is √3 : 2
To find the hypotenuse of a non-right triangle, you can use the Law of Cosines. This theorem states that the square of the length of one side of a triangle is equal to the sum of the squares of the other two sides, minus twice the product of those sides and the cosine of the angle between them. By rearranging the formula and plugging in the known side lengths and angles, you can solve for the length of the hypotenuse.
The hypotenuse of the nth triangle has a length of sqrt(n+1)
7.07 inches.
The length of the hypotenuse is: 10
The circumradius of a right angled triangle would be equal to half the length of its hypotenuse.
A hypotenuse is the longest side of a right angled triangle. The length of a hypotenuse can be found using the Pythagorean Theorem. This states that in a right angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides. This means that to find the length of the hypotenuse, you need to know the lengths of the other two sides.
28.611
Use Pythagoras' theorem...a2 + b2 = c2where c is the length of the hypotenuse in a right-angled triangle.
In a right angled triangle: perpendicular(p), base(b) and hypotenuse(h) are related by the following relation p2 + b2 = h2 On putting the values we get h = 501/2 inches.
Starting with an equilateral triangle of side 2, dropping a perpendicular from one vertex to the opposite base creates two equal right angled triangles with hypotenuse of length 2, base length 1 and height of length √(22 - 12) = √3 which is the longer leg of the 30-60-90 triangle. Thus the ratio of longer_leg : hypotenuse is √3 : 2
It may be of any length but it is always the longest side in a right-angled triangle.
By using the formula a2+b2=c2, where a is one side of the right-angled triangle and b is the other side of the right angle triangle. C stands for the hypotenuse of the right-angled triangle. Note: this formula only works for RIGHT-ANGLED TRIANGLES!!!
The sine of an angle in a right triangle is the ratio of the length of the side opposite the angle to the length of the hypotenuse.In terms of ratios, the sine of an angle is defined, in a right angled triangle, as the ratio of lengths of the opposite side to the hypotenuse.
The altitude/height of an equilateral triangle can be calculated by taking the perpendicular bisector of any side. This line will bisect its opposite angle forming two congruent right angled triangles. The side length of the original equilateral triangle is the hypotenuse and the short leg of right angled triangle is half the hypotenuse. By Pythagoras' Theorem : 42 = 22 + L2.........where L is the length of the altitude. L2 = 42 - 22 = 16 - 4 = 12 L = √12 = 2√3 = 3.464 (3dp)
It will be a right angled triangle with sides of 3 and 4 units with an hypotenuse of 5 units in length.
a2 +b2 = c2 (c is the longest side/or hypotenuse)