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By Pythagoras,

Hypotenuse2 = Base2 + Perpendicular2

So perpendicular2 = Hypotenuse2 - Base2 = (H + B)*(H - B)

= (a + b + a - b) *(a + b - a + b) = 2a*2b = 4ab

So perp = sqrt(4ab) = 2*sqrt(ab)

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Q: What will be the length of the perpendicular of a right angled triangle if its hypotenuse is a plus b and the base is a-b?
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