if any number is said to be divisible by 5.... it means that when you divide that number by 5, the remainder will be equal to 0.... Eg: 125/5=0 so.... 125 is divisible by 5.......
250 is divisible by 1, 2, 5, 10, 25, 50, and 250.
YES!!!! Add the digits , if they sum to '9' then it is divisible by '9'. 1125 ' 1+ 1 +2 + 5 = 9 Hence 1125 is divislble by '9' 1125/ 9 = 125 The answer
Dividing 125 by 3 does not give an integer result. The sum is equal to 41.6 recurring (that is, 41.6666... or 41 and two thirds).
xy + xy = 2xy
125 is divisible by 5 but not by 10 unless you want an answer as a decimal
No. Ten is not evenly divisible by 125.
625 Is divisible by 5
256 125 is not a multiple of 4 so is not divisible by 4 without a remainder.256 125 ÷ 4 = 64031.25
12,500
43,750
yes! 15.625
Yes, but you wont get an integer. 120 and 135 are divisible to an integer.
if any number is said to be divisible by 5.... it means that when you divide that number by 5, the remainder will be equal to 0.... Eg: 125/5=0 so.... 125 is divisible by 5.......
A direct variation is when the value of K in multiple proportions is all divisible by the same number for example: XY=(1)(10) K=10 XY=(2)(20) K=40 XY=(3)(30) K=90 XY=(4)(40) K=160 In this situation the constant (K) of each proportion is divisible by 10 making the multiple equations a direct variation.
125 if you include 1000.
It could be: x*y = 20 and so 523*20 = 10460 which is divisible by 4 and 5 with no remainders