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What would be the diagonal measurement of a 43 inch by 25 inch rectangle be?
Wiki User
∙ 13y ago
The diagonal will be 49.739 inches.
Wiki User
∙ 13y ago
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What is the length of a rectangle whose diagonal is 32 inch?
The diagonal of a rectangle does not provide enough information to determine the length of the rectangle. Let L be any real number such that 32/sqrt(2) < L < 32. let B = sqrt(32^2 - L^2) Since L < 32 the above square root exists, and since L > 32/sqrt(2), B < L. So the rectangle with sides of L and B will have a diagonal of 32 inches. But L is any of an infinite number of possible real numbers. Therefore there are infinitely many possible solutions.
How do you get diagonal measurement of a 17x17 inch square?
You use the Pythagorean Theorem, which says that the square of the hypotenuse of a right triangle is the sum of the squares of the other two sides. Two adjacent sides of a square (or any rectangle) together with a diagonal form a right triangle. In the case of a square, the triangle is isosceles. Calling the length of a side of the square (17 inches) one unit, the theorem tells us that the hypotenuse is the square root of 2 units. Therefore the diagonal of the square is 17 times the square root of 2 inches, which is about 24 inches.
The length of the rectangle below is 26.63 inches. If the diagonal makes an angle of 42.6 and ordm with this side find the measure of the width of the rectangle rounded to the nearest tenth of an inch?
The diagonal creates a right angled triangle with one pair of long and short sides - the diagonal is the hypotenuse. We know the angle between the long side (adjacent) and hypotenuse as 42.6°; We want to find the length of the short (width) side (opposite). We can use the Tan ratio: tan = opposite/adjacent → opposite = adjacent × tan → width = 26.63 in × tan 42.6° = 24.487... in → width is 24.5 inches to the nearest tenth of an inch.
What is the perimeter of a rectangle 7' by 8'?
The apostrophe in 7' means 7 inches. This means that there would be two 7 inch sides to the rectangle and two 8 inch sides. Perimeter = 7+7+8+8= 30 inches.
What is the length and width of a 7 inch screen?
7 inches diagonal top to bottom
What is the diagonal measurement of a 85 inch x 98 inch rectangle?
129.73 inches (rounded)
12inch x 12 inch square what is the diagonal measurement?
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
What is the diagonal of 12 inches and 5 inches?
diagonal is 13 inch length of the rectangle of 12 and 5 inches sides
What is the diagonal measurement of the 22 widescreen monitor?
The diagonal measurement of a 22-inch widescreen monitor is 22 inches for the actual viewing portion of the monitor.However,the monitor or television itself would add to this total measurement,which should be taken into consideration when deciding where to put the monitor.
A square has a diagonal which is 30 inches how long in inches is its side?
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
What is the height of a 15 inch tv when the width is 12 inch?
This question can be solved using pythagorus, assuming the screen is a rectangle and 15in is the measurement of the diagonal (hypotenuse) of the screen. a2 = c2 - b2 a2 = 152 - 122 a2 = 225 - 144 = 81 a = 9in
Why you say diagonal size for picture tubes?
It was a sales tactic, it made a picture seem larger. In an old-style television the measurement of a screen might be 13 inches wide by 9 inches high. The diagonal measurement would be almost 16 inches. A 16 inch screen sounds bigger.
What is the diagonal of a 366 inch by 366 inch square?
The diagonal is 517.602 inches.
What is the diagonal of a 101 inch square?
The diagonal of a 101 inch square is about 142.84 inches.
Would a four inch rectangle be similar to a 4 inch square?
Yes they can definitly be similar.
What is the diagonal of an 18 inch square?
The diagonal of an 18 inch square is about 25.46 inches. (18 times the square root of 2).
What is the length of a rectangle whose diagonal is 32 inch?
The diagonal of a rectangle does not provide enough information to determine the length of the rectangle. Let L be any real number such that 32/sqrt(2) < L < 32. let B = sqrt(32^2 - L^2) Since L < 32 the above square root exists, and since L > 32/sqrt(2), B < L. So the rectangle with sides of L and B will have a diagonal of 32 inches. But L is any of an infinite number of possible real numbers. Therefore there are infinitely many possible solutions.
