why is the efficiency of a calorimeter less than 100%
an ideal machine
there is no unit. its usually a percent. so it would be something like joules/joules, which would be nothing.
there is no unit. its usually a percent. so it would be something like joules/joules, which would be nothing.
the end product assuming 100% efficiency would be carbon dioxide and water vapor
In saying what the overall efficiency would be, I suppose you mean for other processes, creating the chemical energy for example, and using the thermal energy. This is impossible to answer, not knowing what these processes are.
Ideal would be 100 percent. But you'll never get it. Due to the principle of conservation of energy, energy efficiency within a closed system can never exceed 100%. At a loutspeaker you have electrical Voltage as input and sound pressure as output. The efficiency of the loudspeaker is really only 1 percent.
Impurities in the substance can cause a greater percent yield. I recommend redoing the lab for better results.
Styrofoam Cup
72 percent
No heat loss = maximum output. There would be no loss of energy, which is an ideal condition.
You would burn it in a calorimeter :-)
Because unavoidably there would be a loss of energy during the process