Let the number be m.
The problem is stated as √(2*m - 11) = 4.
Squaring both sides: (2*m - 11) = 16
Adding 11 to both sides: 2*m = 27
Dividing each side by 2: m = 13.5
Q.E.D.
8
Twice the number is something like 3x2, 4x2.... Squared is 3x3, 4x4. It's one number multiplied by itself twice
The number is -6.
The answer is 11 !
To find the square root of a number you multiply that number by it self twice.(example) the square root of 9 ? the square root of nine is 81 as 9X9=81. square root of 4 ? th square root of is 16 as 4X4=16.
3.45
There aren't any whole numbers that satisfy this.
8
Twice the number is something like 3x2, 4x2.... Squared is 3x3, 4x4. It's one number multiplied by itself twice
-7754
The number is -6.
It's a square number. Square numbers have a factor pair that is the same number twice. When listed, that number occurs once.
2*24.5 = 49
x=-3 or x=5
You want to create an equation for this. The equation should look like this: x^2 - 2x + 4 = 0 Use the quadratic equation to solve it.
Twice. a*a is a squared.
simply see what you can multiply twice to get the number under the square root sign.