1 o'clock 2 o'clock 3 oclock.............9 o'clock 10 o'clock 11 o'clock 12 o'clock
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If the little hand stayed on the 12, the angle would be 120°. Assuming both hands are pointing to 12 o'clock, when the big hand has moved to 20 past (1/3 of the way round) the little hand will have moved 1/3 of the way to the next number (1). So the angle between the hands will be: 1/3 × 360° - 1/3 × 1/12 × 360° = 120° - 10° = 110°.
False. Although both of them are ALWAYS incorrect, the relative error of the first one is smaller. True~ apex
If the hands start off together at midnight, say, then the minute hand must catch up with the hour hand 11 times before they both end up on top of each other again at noon. Hence between one and two o'clock the time when the hands are in the same place is 60/11 = 5.4545... minutes past the hour, between two and three o'clock 2*60/11 = 10.9090... minutes past the hour and so on. So the time you want is 10.91 minutes past 2 o'clock which, to the nearest second, is 2:10:54.
If it is a 12 hour clock then on 9 pm on the Tuesday of the sixth week they will both be correct.
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